Question

A particle of mass 0.5kg travels in a straight line with velocity

Answer 1

Explanation:

body of mass 0.5 kg travels in a straight line with velocity

v = ax3/2

where a = 5 m -1/2 s-1. ...

The potential energy function for a particle executing linear simple harmonic motion is given by

V(x) =kx2/2,

where k is the force constant of the oscillator.

For k = 0.5 N m-1, the graph of V(x) versus x

Answer 2

Mass m=0.5kg

Velocity ,v=ax3/2

a=5m−1/2 s−1

Initial velocity at x=0=0

Final velocity at x=2=10 root2m.s

Work done =change in K.E

= 1/2 m(v2 −u2 )

=  1/2×0.5×[200]=50J

WD=50J