Question

A particle of mass 0.65 Mev/c square as energy of 20 mega e v find its de Broglie wavelength

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Answer 1

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Answer 2

Given - Mass of particle - 0.65 MeV/c²

Energy of particle - 20 MeV

Find - de Broglie wavelength of particle.

Solution - de Broglie wavelength can be calculated by the formula - lambda = h/✓2mE

Mass of particle in kilograms - 1*10-²⁷ kg.

Energy in Joules - 3.2*10-¹² J

Planck's constant - 6.63*10-³⁴ m² kg / s

Keeping the values in equation-

lambda = 6.63*10-³⁴/(✓2*1*10-²⁷*3.2*10-¹²)

lambda = 6.63*10-³⁴/5.8*10-²⁰

lambda = 1.1*10-¹⁴ metres.

Thus, de Broglie wavelength of particle is 1.1*10-¹⁴ metres.