Question

a particle of mass 0.8g is moving at a constant speed 3 *10^2ms^-1.calculate change in momentum when a force of 5N acts on it for 4 seconds​

Answer 1

Given :

▪ Mass of particle = 0.8g

▪ Speed of particle = 3×10² m/s

▪ Applied force = 5N

▪ Time interval = 4s

To Find :

▪ Change in momentum during the given interval of time.

Concept :

↗ This question is completely based on the concept of newton's second law of motion.

↗ As per this law,

Applied force = Rate of change of linear momentum

Mathematically,

• F = ΔP/Δt

Where,

F denotes applied force

ΔP denotes change in momentum

Δt denotes time interval

Calculation :

→ F = ΔP/Δt

→ ΔP = F × Δt

→ ΔP = 5 × 4

→ ΔP = 20 Ns

Answer 2

Answer:

YOUR QUESTION :

A particle of mass 0.8g is moving at a constant speed 3 *10^2ms^-1.calculate change in momentum when a force of 5N acts on it for 4 seconds.

SOLUTION :

Given :

Mass of particle = 0.8g

Speed of particle =

$3 \times {10}^{2}$m/s

Applied force =5N

Time interval =4s

To find :

• Change in momentum during the given interval of time.

Concept :

Applied force = Let of change of Linear momentum.

Mathematically,

• F=∆P/∆t.

Calculation :

F = ∆P/∆t

=>∆P =F×∆t

=>∆P=5×4

=>∆P=20

ANSWER : 20.