Question

A particle of mass 1 kg and charge 1 C moves from rest through a potential of 1 V. Its final velocity will be​

Answer 1

180m/s

Explanation:

Initial separation between the charges r₁ = 1 m Initial potential energy U₁ kq₁92 r1 = 9 × 10⁹ × 10-6 × 2 × 10 1 = 18 J

Initial kinetic energy K₁ = 0

Final separation between the charges r2 = 10 m

Final potential energy U₂ = kq192 r2 9 × 10⁹ × 10-6 × 2 × 10-³ 10 = 1.8 J

Final kinetic energy K₂ = 0 + mv² K2 2 = 1 (0.001)r2 = 10 m

Final potential energy U₂ = kq192 r2 = 9 x 10⁹ x 10-6 × 2 × 10-³ 10 = 1.8 J 1

Final kinetic energy K₂ = 0 + mv²: = (0.001) v² = 0.0005v²

Using energy conservation, K₂ + 1₂ = K₁ + U₁ .. 0.0005v² +1.8 = 0 +18 v = 180 m/s