Question

A particle of mass 1 kg has a velocity of 2 m/s.
A constant force of 2 N acts on the particle for 1 s in a
direction perpendicular to its initial velocity. Find the velocity
and displacement of the particle at the end of 1 s.

Answer 1

Answer:

the velocity is

$\sqrt{5}$

and displacement is 0.5 m.

Explanation:

As initially mass is moving in x-axis( let).

the force applied is perpendicular to velocity let In y-axis. so velocity in y-axis is 1m/s from v=u+at

as u in Y-axis is zero and a=F/m=1m/s^2 and t=1 sec. So we have velocity in x and y-axis hence we take resultant velocity which is √5m/s .Now by using third equation of motion we get displacement as 0.5 m