A particle of mass 1 kg is moving in the xy-plane whose position at an instant t is
r = 3 sin 2ti+ 3(1 - cos 2t)), where r is in metre and t is in second. Find the kinetic energy of the
particle at an instant t.
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Answer:
convert unit vector in x and y coordinate
x=3sin2t
y=3 (1-cos2t)
then differentiate w.r.t t you will get the th value of velocity in x and y direction
find resultant of velocity
apply the formula of kinetic energy
1/2mv^2
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