A particle of mass 1 kg is performing SHM and its displacement any time is given by
y=2sin(pi/12 t + pi/6)m
What will be kinetic energy of particle at t = 2 sec?
1.pi^2/288J
2.pi^/144J
3.pi/288J
4.pi/144J
Answers
Answer:
pi^2 / 288
Explanation:
differentiate the given y eqn
v= dy/dt----------> 1
K=1/2 mv^2---------> 2
Sub eqn 1 in eqn 2,
We get answer as pi^2/288
Answer:
The kinetic energy of the particle at t = 2 sec will be i.e.none of the options are correct.
Explanation:
The kinetic energy of the body at a particular instant is given as,
(1)
Where,
K=jinetic energy of the body
m=mass of the body
ω=angular frequency of the body
y=instantaneous displacement of the body
The waveform given in the question is,
(2)
By substituting the value of "t" i.e. 2 seconds in equation (2) we get;
()
(3)
The equation (2) is of the form,
(4)
So, by comparing equation (2) with equation (3) we can say,
A=2m
By substituting all the required values in equation (1) we get;
Hence, the kinetic energy of the particle at t = 2 sec will be i.e.none of the options are correct.