Question

A particle of mass 1 kg is revolved in a horizontal circle of radius 1 m with the help of a string. If the maximum tension the string can withstand is 16π^2 N, then the maximum frequency with which the particle can revolve is​

Answer 1

Answer:

A mass m=1 kg is revolved around a horizontal circle (thus no effect of graffiti )

along a radius of r=1m.

The man experiences a centripetal force :

Fe=mrw2 [w : Angular frequency ] 

This centripetal force is provided by the tension is string.

⇒T=Fe=mrw2

as given T=16π2 N, we get :

16π2=(1)(1)w2

⇒w2=16π2⇒w=4π

Thus, frequency of rotation.

v=2πw=2.

Explanation:

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Answer 2

Answer:

2 Hz

Explanation:

Using,

mrw^2 = T and w = 2 πn

so, n = 1/2π √T/ mr

n= 2 Hz