Question

A particle of mass 1 kg is rotated by means of a string in vertical circle with a constant speed the difference in the tension at the bottom and top would be

Answer 1

The tension at any point on the circular path is given by T=(m/R)(u

2

+gr−3gh); h is the height of the point from the horizontal

For a full circle, h=2R Substituting, we get, T

H

=(m/R)(u

2

−5gR) and

at the bottom point of the circle , h=0 and thus, T

L

=(m/R)(u

2

+gR)

The difference in tension will be (T

L

−T

H

)=(m/R)(6gR)=6mg

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