Question

A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 × 10^6 ms^-1.the velocity of particle is ( mass of electron = 9.1 ×10^-31 kg )​

Answer 1

=> 2.7 × 10^-18 ms^-1

Explanation:

According to de - Broglie relation wavelength of a particle is given by

λ = h/p

Where, h is Planks constant and the wavelength of an electron is given by

λe = h / pe

λ = λe, so p = pe

meve = mv

v = me ve / m

Here,

me = 9.1 × 10^-31 kg

ve = 3 × 10^6 ms^-1

m = 1mg

m = 1 × 10^-6 kg

∴ v = (9.1 × 10^-31 × 3 × 10^6) / 1 × 10^-6

∴ v = 2.7 × 10^-18 m/s

The Velocity is 2.7 × 10^-18 ms^-1 !

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