Question

A particle of mass 10 gram moves along a circle of radius 6.4 cm with a constant tangential acceleration what is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8 into 10 to the power minus4joule by the end of second revolution after the beginning of motion

Answer 1

Explanation:

12mv2=E⇒12(101000)v2=8×10−4

⇒v2=16×10−2⇒v=4×10−1=0.4m/s

Now, v2=u2+2ats(s=4πR)

⇒16100=02+2at(4×227×6.4100)

⇒at=16100×7×1008×22×6.4=0.1m/s2