Question

A particle of mass 10 mg is in equilibrium in a verticle electric field E=10 raise to power 5 j cap the charge on particle is

Answer 1

Answer:

Explanation:mass of particle, m = 10mg = 10^-6 Kg

electric field intensity,

Let the charge on the particle is q.

so, force acting due to electric field on charged particle , F = qE

= q × N

gravitational force acting on body, W = mg

=

= N

net force acting on particle , Fnet = F + W

=

at equilibrium,

Fnet = 0

so, q × 10^5 j = 10^-5 j

or we can write , 10^5 q = 10^-5

so, q = 10^-10 C

hence, charge on particle is 10^-10 C

Answer 2

Answer:

9.8×10to the power minus 4

Explanation:

E=f\q ,f=mg,E=given and then simple calculation