Question

A particle of mass 100 g is thrown vertically
upwards with a speed of 5 m/s. The work done
by the force of gravity during the time the particle goes up is
(a) –0.5 J (b) –1.25 J
(c) 1.25 J (d) 0.5 J

Answer 1

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Answer 2

$\Large\boxed{\sf{(b)\quad\!\!-1.25\ J}}$

Given,

$\sf{m=100\ g=0.1\ kg}$

$\sf{u=5\ m\ s^{-1}}$

We know the particle attains zero velocity at its maximum height.

$\sf{v=0\ m\ s^{-1}}$

Then the work done by the force of gravity is, by work - energy theorem,

$\longrightarrow\sf{W=\dfrac{1}{2}m\left(v^2-u^2\right)}$

$\longrightarrow\sf{W=\dfrac{1}{2}\times0.1\left(0^2-5^2\right)}$

$\longrightarrow\sf{W=-\dfrac{1}{2}\times0.1\times25}$

$\longrightarrow\sf{\underline{\underline{W=-1.25\ J}}}$