Question

A particle of mass 100g is fired with a velocity of 20ms making an angle of 30° with the horizontal.When it rises to the point of its highest point, find the change in momentum

Answer 1

Hello Dear,

◆ Answer -

∆p = -1 kgm/s

◆ Explanation -

# Given -

m = 100 g = 0.1 kg

u = 20 m/s

θ = 30°

# Solution -

We know that, horizontal velocity of projectile is always constant. Thus horizontal momentum is zero. i.e. ∆px = 0

So now change in momentum is given by -

∆p = ∆px + ∆py

∆p = 0 + m (uy - u)

∆p = m (u.sinθ - u)

∆p = 0.1 (20 × sin30° - 20)

∆p = 0.1 × 20 (0.5 - 1)

∆p = -1 kgm/s

Therefore, magnitude of change in momentum will be -1 kgm/s.

Thanks dear...