A particle of mass 10g is moving with a velocity 2i+j+3k(cm/s). magnitude of its linear momentum is
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Answer:
Position vector
r
=
i
^
+
j
^
Velocity
v
=2
i
^
+3
j
^
m/s
Mass m=2 kg
Angular momentum
L
=m(
r
×
v
)
⟹
L
=2[(
i
^
+
j
^
)×(2
i
^
+3
j
^
)]=2
k
^
Explanation:
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