Question

A particle of mass 10g is placed in potential field given by v= (50x^2+100)erg/g. what will be the frequency of oscillation?

Answer 1

Answer:

f=1.81*10^43 hertz

Step-by-step explanation:

Given That:

v=(50*10^2+100)erg/g

1 erg=9.11*10^-4 joules

so,

v=(0.04*10^2+0.06)joule/g

mass=m=10g

To Find:

f=?

Solution:

we know that

f=c÷wavelength.............(i)

here

c= speed of light

and

wavelength=h/(m*v)...........(ii)

here

h=plank constant, v=potential,m=mass

put the values in (ii)

wavelength=6.626*10^-34/(10*0.04*10^2+0.06)

wavelength=1.65*10^-35 m

put in (i)

f=3*10^8/1.65*10^-35

f=1.81*10^43 hertz   answer