Question

a particle of mass 10g is undergoing SHM of amplitude 10cm and period 0.1 s .The maximum value of force on particle is about

Answer 1

I hope it is correct....☺☺☺☺☺

Answer 2

Dear Student,

● Answer -

F = 3.948 N

● Explanation -

# Given -

m = 10 g = 0.01 kg

A = 10 cm = 0.1 m

T = 0.1 s

# Solution -

Maximum acceleration is given by formula -

a = Aw²

a = A × (2π/T)^2

a = 0.1 × (2π/0.1)^2

a = 0.1 × (20π)^2

a = 40π^2

Maximum value of force on particle -

F = ma

F = 0.01 × 40 × π^2

F = 3.948 N

Hence, maximum value of force on particle is 3.948 N.

Thanks dear. Hope this helps you...