Question

A particle of mass 10kg is moving in a straght line.the variation of its displacemnt ,x with t(in seconds) is given by x=(t^3-2t-10)m. The force acting on it at t=4secs,is

Answer 1

Answer:

Explanation:

Solution:

dx

dt

v=

3t² - 2

dv dx a= = (3 × 2)t = 6t = 6 × 4 = 24 m

Force = m x a = 10 x 24

= 240 N.