Question

A particle of mass 15 kg an initial velocity

^ ^

v = i - 2 j m / s.

→

1 It collides with another body and the

impact time is 0.1 s, resulting in a velocity

^ ^ ^

v = 6 i + 4 j + 5k m / s.

→

f after impact. The average force

of impact on the particle is :

(a)

^ ^ ^

15 5 i + 6 j + 5k (b)

^ ^ ^

15 5 i + 6 j - 5k

(c)

^ ^ ^

150 5 i - 6 j + 5k (d)

^ ^ ^

150 5 i + 6 j + 5k​

Answer 1

I do not no this answer but i can try

Answer 2

The average force  of impact on the particle is $150(5i+6j+5k)\ N$.

Explanation:

It is given that,

Mass of the particle, m = 15 kg

Initial velocity of the particle, $u=(i-2 j)\ m / s.$

Final velocity of the particle, $v=(6 i+4 j+5k)\ m / s$

Time of impact, t = 0.1 s

Let F is the average force  of impact on the particle. It is given by the the formula of acceleration which is equal to the change in velocity per unit time  of the particle such that,

$F=m(\dfrac{v-u}{t})$

$F=15(\dfrac{((6 i+4 j+5k))-((i-2 j))}{0.1})$

$F=150(5i+6j+5k)\ N$

So, the average force  of impact on the particle is $150(5i+6j+5k)\ N$. Hence, this is the required solution.

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