Question

A particle of mass 1g moving with a velocity V1=3i-2j experiences a perfectly inelastic collision with another particle of mass 2g and velocity V2=4j-6k .Find the velocity vector and the magnitude of the particle. Please answer fast.

Answer 1

Explanation:

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Answer 2

Velocity vector, $V=(3.67i-4.67j)\ m/s$

Magnitude of velocity, V = 5.93 m/s

Explanation:

It is given that,

Mass of object 1, $m_1=1\ g=0.001\ kg$

Speed of object 1, $v_1=(3i-2j)\ m/s$

Mass of object 2, $m_2=2\ g=0.002\ kg$

Speed of object 2, $v_2=(0i+4j-6k)\ m/s$

Let V is the final velocity of particles in case of inelastic collision. the momentum remains conserved. Using the conservation of linear momentum to find it as :

$m_1v_1+m_2v_2=(m_1+m_2)V$

$0.001\times (3i-2j)+0.002\times (0i+4j-6k)=(0.001+0.002)V$

$0.003i-0.002j+0.008i-0.012j=0.003V$

$0.011i-0.014j=0.003V$

$V=(3.67i-4.67j)\ m/s$

Magnitude of V,

$|V|=\sqrt{3.67^2+(-4.67)^2}$

|V| = 5.93 m/s

Hence, this is the required solution.

Learn more :

Inelastic collision

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