Question

A particle of mass 1kg has a velocity of 2m/s. A constant force of 2N acts on the particle for 1s in a direction perpendicular to its initial velocity. Find the velocity and displacement of the particle at the end of 1s.

Answer 1

Hi friend,

Let particle be moving along x axis 

and the force is acting along y axis.

As F=ma

a =F/m

   =(2m/s2 ) j      

 =>   v = 2i                           (given)

For constant acceleration we can use the formula,

v=u+at and s=ut+at2 /2

After 1 sec

v = 2i + 2j  

   = 2√2 in magnitude

Now,
s = 2i+ j = √5

Total displacement = √5 m

Hope it helps!

Answer 2

Answer:

hope this will help you to solve your doubt