Question

A particle of mass 1kg is thrown upward with velocity 10m/s. Find magnitude of charge in momentum of the particle by the time it come back​

Answer 1

Answer:

20 kgm/s

Explanation:

We know that, momentum, P= mv, P and v are vectors.

Let the upward direction be positive.

Then,

1) The particle is going up.

So, P(initial) = 1×(+10) kgm/s

2) The particle returns down, just hits the ground

So, P(final) = 1×(-10) kgm/s (Downward direction is negative)

Change, ΔP= P(final)- P(initial)

= -10 - (+10)

= -20 kgm/s

Magnitude, |ΔΡ|= 20 kgm/s