Question

A particle of mass 2.4 kg is having a
velocity of 3i+41 m/s at (5,6)m. The angular
momentum of the particle about (1,2)m, in
kg m/s, is​

Answer 1

Step-by-step explanation:

Position vector

r

=

i

^

+

j

^

Velocity

v

=2

i

^

+3

j

^

m/s

Mass m=2 kg

Angular momentum

L

=m(

r

×

v

)

⟹

L

=2[(

i

^

+

j

^

)×(2

i

^

+3

j

^

)]=2

k

^

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