Question

A particle of mass 2 kg experiences two forces,F1= 5i+8j+7k and F2=3i-4j+3k. what is the acceleration of the particle

Answer 1

F = ma
a = F/a

Here, two forces are acting therefore
a = F1 + F2/m
a = 5i + 8j + 7k + 3i - 4j +3k/2
a = 8i + 4j + 10k/2
a = 2(4i + 2j + 5k)/2
a = 4i + 2j +5k m/s²

Answer 2

The acceleration of the particle is 4i+2j+5k m/s².

Given:-

Mass of the particle = 2kg

First force = 5i+8j+7k

Second force = 3i-4j+3k

To Find:-

The acceleration of the particle.

Solution:-

We can simply calculate the acceleration of the particle by using these simple steps.

As

Mass of the particle (m) = 2kg

First force (F1) = 5i+8j+7k

Second force (F2) = 3i-4j+3k

Now, According to the second law of motion,

F = m×a

a = F/m

Here, since we have two forces, we will take their sum as a final force,

a = (F1+F2)/m

on putting the values,

a = (5i+8j+7k) + (3i-4j+3k)/2

a = (5i+3i) + (8j-4j) + (7k+3k)/2

a= 8i+4j+10k/2

a = 4i+2j+5k m/s²

Hence, The acceleration of the particle is 4i+2j+5k m/s².

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