Question

A particle of mass 2 kg is moving along a circular path of radius 1m. If the angular speed is 2 radian per second ,what will be its centripetal force?

Answer 1

Centripetal force acting on the rotating body and it is directed to the center of that circular path.

We know that the,

Centripetal force = mrω² ------- (1)

m = mass of the particle = 2 kg

r = radius of the circular path = 1 m

ω = angular speed of the particle = 2 rad/s

Now we can substitute above values in to the equation (1),

Centripetal Force = 2 * 1* 2^{2}

                             = 2 * 1 * 4

                             = 8 N

Answer : Centripetal Force = 8 N

Answer 2

Given conditions,

Mass =- 2 kg.

Radius of the Circular Path = 1 m.

Angular Speed = 2 radian/seconds.

Using the Formula,

Centripetal Force = mv²/r

∴ Centripetal Force = mrω²

∴ Centripetal Force = 2 × 1 × 2²

∴ Centripetal Force = 8 N.

Hence, the Centripetal force acting on the body moving in circular path is 8 N.

Hope it helps.