A particle of mass 2 kg is moving along line AB
according to y - x - 4 with speed 4 m/s, then
magnitude of angular momentum about 'O'is
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I think question is ---> A particle of mass 2 kg is moving along 'AB
according to y = x - 4 with speed 4 m/s, then
angular momentum about 'O' is
(1) 16√2 kg m/s
(3) 32 kg m/s
(2) 32√2 kg m/s
(4) 16 kg m/s
solution : see figure, we have to find out perpendicular distance from O to P.
here, we have to find out angular momentum of particle P about origin O.
given, equation of line y = x - 4
or, y = (1)x - 4
hence, slope of line , m = 1 = tanα
so, α = 45° , angle made by line with positive x-axis is 45°.
now see figure, we have to find OP
here, OP = r = 4cos45° = 2√2
then angular momentum = mvr
= 2kg × 4 m/s × 2√2
= 16√2 kg m/s
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