Question

A particle of mass 2 kg is moving in circular pa
when particle travels from A to P will be
ng is moving in circular path with constant speed 20 m/s. The magnitude of change in velocity when particle travels from A to P will be
(2) 40 m/s
(1) 20root2 m/s
(3) 40,root2 m/s
(4) Zero


Ans with explanation
I'll mark it as a branlist ans​

Answer 1

Answer:

heres ur answer

Explanation:

Change velocity

         vector

20i-20j    (∵xi-yj)

=magnitude find

=√(20)²+(20)²

=20√2m/s

Answer 2

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal 20{\sqrt{2}}m/s}}$

$\huge\underline\orange{\mathcal Solution}$

Given :-

Mass (M) = 2 kg

Speed (v) = 20m/s

Now Taking Component Of A and P :-

$\large{\mathcal Va= 20 î}$

$\large{\mathcal Vb = 20 j}$

When particle travel From A to P The magnitude Change in velocity will be :-

$\large{\mathcal v ={\sqrt{{Va}^{2}+{Vb}^{2}}}}$

$\large{\mathcal v ={\sqrt{{20}^{2}+{20}^{2}}}}$

$\large{\boxed{\mathcal v =20{\sqrt{2}}}}$

Hence, The magnitude of change in velocity will be 20√2 m/s