Question

A particle of mass 2 kg is moving on a circular path of radius 10 m with a speed of 5 m/s then the force acting on it is​

Answer 1

Given:

A particle of mass 2 kg is moving on a circular path of radius 10 m with a speed of 5 m/s.

To find:

Force acting on it ?

Calculation:

Since the particle is moving in a circular trajectory with a uniform speed, it will only experience the force due to centripetal acceleration directed radially inwards towards the centre of the circle.

$\rm \therefore \: centripetal \: force = \dfrac{m {v}^{2} }{r}$

$\rm \implies \: centripetal \: force = \dfrac{2 \times {(5)}^{2} }{10}$

$\rm \implies \: centripetal \: force = \dfrac{2 \times 25 }{10}$

$\rm \implies \: centripetal \: force = \dfrac{50 }{10}$

$\rm \implies \: centripetal \: force = 5 \: N$

So, the object will experience of force of 5 N.

Additional Information:

• We are considering only centripetal force because the particle is performing uniform circular motion.

• However, if the particle would have experienced tangential acceleration, we would have also considered a tangential force.

• In that case , the net force experienced by the particle would have been the vector addition of centripetal force and tangential force.

$\star$ Hope It Helps.