A particle of mass 2 kg moving with velocity 3m/s is acted upon by a force which changes its direction of motion by an angle 90° without changing its speed. What is the magnitude of impulse experienced by particle
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Impulse=Change in momentum
Impulse=m(v-u)
=2kg×(0-3)m/s
= -6Ns
Magnitude of impulse is 6Ns
Hope this helps.
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