Question

A particle of mass 2 kg starts moving in a straight line with a velocity v = 5x ^2 m/s
the work done the net force during displacement from x=0 to x= 2 m is
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Answer 1

Answer:

Given, mass=2kg,velocity=a x

Since, v=a x,v=a 4

So,V2=u2+2as⇒v2−u2=2as⇒v2

=2as→a=V2/2s Since, u=0

a=2a2/2s=4a2/4r2⇒a=a2/2

So, workdone=f×ds=2×a2/2×4=4a2