Question

A particle of mass 2 kg travels according to equation S=3t³+2t . Find the work done on 3 sec of its motion​

Answer 1

Answer:

9396 newton meter is the answer.

may it help you

Answer 2

The work done on 3 sec of its motion​ is 6885 J.

Explanation:

It is given that,

Mass of the particle, m = 2 kg

Displacement of a particle as a function of time t is given by :

$s=3t^3+2t$

Velocity of the particle is given by,

$v=\dfrac{ds}{dt}=9t^2+2$

If u and v are initial velocity. So,

At t = 0 s, u = 2 m/s

At t = 3 s, $v=9(3)^2+2=83\ m/s$

Work done is equal to the change in kinetic energy as,

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 2\times ((83)^2-2^2)$

W = 6885 J

So, the work done on 3 sec of its motion​ is 6885 J. Hence, this is the required solution.

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