Question

A particle of mass 2 kg travels along a straight line
with velocity v = avx, where a is a constant. The
work done by net force during the displacement of
particle from x = 0 to x = 4 m is
(1) a²
(2) 22²
(3) 42²
(4) √2a²
​

Answer 1

Answer:

Explanation:

If i am not wrong the there is some quite of confusion ,when v = avx ,then a for acceleration is av*2

now works = force ×displacment f is mav*2

And d is 0 to 4 on putting values we ge w= 8 av*2 so that's not option so if i am wrong sorry !