A particle of mass 2 kg Travels along a straight line with velocity V =a√x where is a constant. work done by the net force during the displacement of x= 0 to x= 4m is?
danger2776:
mine method is easy one
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Answered by
146
Hi..
Hope this helps u!
Hope this helps u!
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Answered by
78
Here's your answer buddy,
V=a\
a=\=2a
v^2-u^2=2as (u=0)
a=v^2/2s= (2a)^2/2*4
= 4a/4*2= a^2/2 (acceleration)
w=f*s=ma*s
= 2*a^2/2*4
=4a^2 (answer)
hope it helps
please mark it as brainliest
V=a\
a=\=2a
v^2-u^2=2as (u=0)
a=v^2/2s= (2a)^2/2*4
= 4a/4*2= a^2/2 (acceleration)
w=f*s=ma*s
= 2*a^2/2*4
=4a^2 (answer)
hope it helps
please mark it as brainliest
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