Question

A particle of mass 2 kilogram is moving along x-axis its position at any time t is given as x =t^2.the total work done by the force acting on it in time interval t=0 to t=5 second is

Answer 1

As x=t², therefore, velocity (v)=2t and so acceleration(a)=2m/s².

So, force(F) acting on body=ma=2×2=4 N

So, work = F×(displacement)=4×(25-0)=100 J