A particle of mass 20 g moves along a circle of radius 16 cm with a constant tangential acceleration, the magnitude of change in momentum after one revolution of motion starting from rest is 8 × 10−2 kg m/s. The magnitude of tangential force on the particle is
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r= π 20
In two revolution , distance is s=2×2πr=80m
Now, v 2 =2as for zero initial speed.
⟹a= v^2/2s
= 80×80/2×80
⟹a=40m/s^2
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