A particle of mass 200 g executes a simple harmonic motion . the restoring force is provided by a spring of spring constant 80 N/m.Find the time period?
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M = 200g = 0.2kg
Spring force = 80N/ m
T = 2 X pi X root under 0.2/80
T= 2pi X root 2/800
T = 2pi X 1/20
T = 0.31 sec
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