Physics, asked by dishapatel6203, 9 months ago

A particle of mass 200g executes SHM the restoring force is provided by the spring of force constant 80 Newton per metre what is the time period of oscillation

Answers

Answered by siddharthnagar667

2

The time period is

T=2π

k

m

=2π

80N/m

200×10

−3

kg

=2π×0.05s=0.31s

Answered by snehasr2014

0

Answer:T=2PIROOTM/K

2PIROOT200/80000

2PIROOT1/400

2PI1/20

Explanation:

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