a particle of mass 200g is whirled into a vertical circle of radius 80cm using a massless string the speed of the particle when the string makes an angle 60 with vertical line is 1.5m/s the tension in the string at this position is
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Answered by
192
Given :mass=200g=200/1000=0.2kg
r=80cm=80/100=0.8m
θ=60
speed=v=1.5m/s
Formula to be used :
Centripetal force=F=mv²/R
=0.2x1.5.1.5/0.8
F=0.56N
Tension =mv²/R+mgcosθ
=0.56 +0.2x10x cos 60
=0.56+2x1/2
=1.56N
∴Tension in the string is 1.56N
r=80cm=80/100=0.8m
θ=60
speed=v=1.5m/s
Formula to be used :
Centripetal force=F=mv²/R
=0.2x1.5.1.5/0.8
F=0.56N
Tension =mv²/R+mgcosθ
=0.56 +0.2x10x cos 60
=0.56+2x1/2
=1.56N
∴Tension in the string is 1.56N
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35
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