Question

A particle of mass 2kg executing SHM has amplitude 20 cm and time period 1 second its maximum speed is?

Answer 1

Hey mate,

◆ Answer-
vmax = 1.256 m/s

◆ Explaination-
# Given-
m = 2 kg
A = 20 cm = 0.2 m
T = 1 s

# Solution-
Angular velocity is calcualted by-
ω = 2π/T
ω = 2π/1
ω = 2π

In SHM, maximum velocity is given by-
vmax = Aω
vmax = 0.2 × 2π
vmax = 1.256 m/s

Threfore, Maximum speed of the particle is 1.256 m/s.

Hope it helps...

Answer 2

Answer:

Here is the solution

Explanation:

Given-

m = 2 kg

A = 20 cm = 0.2 m

T = 1 s

# Solution-

Angular velocity is calcualted by-

ω = 2π/T

ω = 2π/1

ω = 2π

In SHM, maximum velocity is given by-

vmax = Aω

vmax = 0.2 × 2π

vmax = 1.256 m/s

Threfore, Maximum speed of the particle is 1.256 m/s.