A particle of mass 2kg is moving in circular path of radius 10m with a speed of 5m/s and its speed is increasing at rate of 3m/s find force acting on it
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Explanation:
A particle is moving on a circular path of 10m radius. At any instant of time its speed is 5m/s and the speed is increasing at a rate of 2m/s
2
. At this instant the magnitude of the net acceleration will be nearly.
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ANSWER
Net acceleration is the resultant acceleration of centripetal acceleration and tangential acceleration thus find both of them as follows:
A
c
− be centripetal acceleration.
A
t
− be tangential acceleration
A
net
=
(A
c
2
+A
t
2
)
Now then,
A
c
is
R
V
2
=
10
25
=2.5m/s
2
A
t
is given as 2.m/s
2
, thus
A
net
=
(2.5
2
+2
2
)
=3.20m/s
2
.
Hence,
option (A) is correct answer.
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