Question

A particle of mass 2kg is moving with a uniform speed of 10m/s in x-y plane along the line x= 6m. Find the magnitude of the angular momentum of the particle about the origin
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Answer 1

Answer:

120

Explanation:

3y=4x+10

|p⃗ |=mv=10×6=60kgm/s

The ⊥ distance form origin on line

=−0'+0+10(3)2+(4)2−−−−−−−−−√=1056=2m

|L|=P×⊥dist=(60)(2)=120kg−m2/s.

Alternatively

tanθ=4/3

θ=53∘

r=52sin53∘=2m

L=rP⇒L=rmv

L=2×10×6

L=120Kg−m/s.

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