Question

A particle of mass 2kg starts its motion from the
origin (0, 0, 0) from rest under the influence of
force (2i +3j+4K) N. Find -
(i) Displacement in 4 sec.
8i+12j+16k (2) 8i+10j+16k
(3) 8i+ 10+18k (4) 101+12j+18k
(ii) Final position vector after 4 sec.
(1) 8+12 +16k (2) si +109+16k
(3) 8i+10j+18k (4) 10i+12j+18k
(iii) Final coordinates after 4 sec.
(1)8,12,16
(2) 8, 10, 16
(3) 8, 10, 18
(4)10,12,18

Answer 1

1. The displacement of the body in 4 second =( 8i + 12j +16k) option 1

2.the final position after 4 second=( 8i + 12j +16k) option 1

3. the final co-ordinate after 4 second (8,12,16) option 1

Explanation:

• The displacement of the body is given by the formula, S= ut+1/2a. t² . share the body starts from rest and hence the initial velocity is equal to zero.

F=ma, hence a= F/m hence a= (1 i +1.5 j + 2 k)

The displacement =( 8i + 12j +16k)

• Since the object starts from the axis hence the displacement of the body is the final location of the object.

• The  position of the object after 4 second is =( 8i + 12j +16k)=( 8i + 12j +16k)

To know more about displacement,

why is displacement reaction also called a substitution reaction ..

.https://brainly.in/question/11481326