Question

A particle of mass 30g performs vertical circular motion at a place where g is 10m/s^2. If the maximum change in its potential energy during the motion is .6J the radius of path is​

Answer 1

Answer : The radius of the path is 10 m.

Explanation :

It is given that,

Mass of the particle, m = 30 g = 0.03 Kg

Acceleration due to gravity, $g = 10\ m/s^2$

Maximum change in potential energy, $\Delta\ PE=6\ J$

Let r be the radius of the path.

We know that the potential energy of the particle is given by

PE = m g h

Here, h = 2r

So, PE = mg(2r)

$6\ J=0.03\ kg\times 10\ m/s^2\times 2r$

$r=10\ m$

So, the radius of the path is 10 m.