A particle of mass 4 kg at rest is acted upon by a force 20 n for 4 s. its kinetic energy after 4 seconds is
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Mass = 4kg
Force= 20N
Time = 4s
K.E.=?
W.k.t.
K.E.= 1/2mv²
Therefore
F=ma
20=4(a)
a=5ms^-2
so,a=v/t
v=a.t
v=20ms^-1
So,K.E=1/2(4)(20)²
=800 Joule.
Force= 20N
Time = 4s
K.E.=?
W.k.t.
K.E.= 1/2mv²
Therefore
F=ma
20=4(a)
a=5ms^-2
so,a=v/t
v=a.t
v=20ms^-1
So,K.E=1/2(4)(20)²
=800 Joule.
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