Physics, asked by fatemapervin82, 10 months ago

A particle of mass 40 kg gains a velcity of 15 ms when force applied.what is the magnitude of the force applied and kinetic energy after 4s

Answers

Answered by juhi2606
0

Answer:

m=40kg

v=15m/s

p= mv

p=40×15=600

f=p/t

here t=4sec

so f=600/4 =150newton

now..k.e=1/2mv^2

=1/2×600×15

=300×15

=4500 joule

Answered by himanshisahu0620
0

Given

Mass = 40kg

Velocity 15m/s

Time=4s

F=?

Ke=?

F= m×a

and a=v/t

F= mv/t

F= 40×15/4

= 150N (answer)

And formula of kinetic energy is ½mv²

KE= ½×40×15²

=4500J (answer)

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