A particle of mass 40 kg gains a velcity of 15 ms when force applied.what is the magnitude of the force applied and kinetic energy after 4s
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Answer:
m=40kg
v=15m/s
p= mv
p=40×15=600
f=p/t
here t=4sec
so f=600/4 =150newton
now..k.e=1/2mv^2
=1/2×600×15
=300×15
=4500 joule
Answered by
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Given
Mass = 40kg
Velocity 15m/s
Time=4s
F=?
Ke=?
F= m×a
and a=v/t
F= mv/t
F= 40×15/4
= 150N (answer)
And formula of kinetic energy is ½mv²
KE= ½×40×15²
=4500J (answer)
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