Physics, asked by asllaiswarya, 5 months ago

a particle of mass 50g moves on a straight line ​

Answers

Answered by nagavinothinirm3
0

Answer:

m=50g=5×10

−2

kg

As shown in the figure.

Slope of OA=tanθ

OD

AD

=

3

15

=5 m/s

2

So, at t=2 sec acceleration is 5 m/s

2

Force =ma=5×10

−2

×5=0.25 N along the motion.

At t=4sec

slope of AB=0, acceleration =0[tan0

o

=0]

∴ Force =0

At t=6 sec, acceleration = slope of BC

In ΔBEC=tanθ=

EC

BE

=

5

15

=5.

Slope of BC=tan(180

o

−θ)=−tanθ=−5 m/s

2

(deceleration)

Force =ma=5×10

−2

5=0.25 N. Opposite to the motion.

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