Question

A particle of mass 5g is moving with a uniform speed of 3sqrt2 cm//s in the x-y plane along the line y=x+4. The magnitude of its angular momentum about the origin in g cm^(2)//s is

Answer 1

Answer:

the particle that is given is same

Answer 2

Answer:

60 g cm² / sec

Explanation:

Given :

Motion of particle along line :

= > y = x + 4

Mass of particle = 5 g

Velocity of particle = 3 √ 2 cm / sec

We know :

Angle momentum = Cross product of Radius and linear momentum .

= > L = r m v sin Ф

= > m v r sin Ф  ... ( i )

Now refer to attachment :

cos 45 = OM / 4

OM = 4 / √ 2

OM = 2 √ 2 cm

OM is also equal to r sin Ф

Putting values in ( i ) we get :

L = 5 g × 3 √ 2 cm / sec × 2 √ 2 cm

L = 60 g cm² / sec

Therefore we get required answer.