Question

A particle of mass 5kg is kept at the point 2i + 3j + 7k. Another particle of mass 3kg is kept at the point having position vector 5i – 7j –k. Find the position vector of the CoM. If no external force is acting on the system, how would the position of CoM change?

Answer 1

Answer:

I hope it is helpful

Explanation:

We know that,

L

=m(

r

×

v

)

L

=m[(10

i

^

+6

j

^

)×(5

i

^

)]

L

=m

∣

∣

∣

∣

∣

∣

∣

∣

i

^

10

5

j

^

6

0

k

^

0

0

∣

∣

∣

∣

∣

∣

∣

∣

L

=m[[(10)(0)−(5)(6)]

k

^

+[(6)(0)−(0)(0)]

i

^

+[5(0)−10(0)]

j

^

]

L

=(0.01)[−30

k

^

+(0)

i

^

+(0)

j

^

]

L

=−0.3

k

^

Joule sec

Option A is correct.