Question

A particle of mass 70 g, moving at 50 cm/s, is acted upon by a variable force opposite to its direction of motion. The force F is shown as a function of time t.

Answer 1

The impulse given to the particle is equal to the area under the F–t graph = 0.07 kg m/s = 2 x initial momentum of the particle. Hence, the particle will reverse in direction and move with its initial speed.

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