A particle of mass m =0.5 kg travels in a straight line with velocity v=5x^3/2 find the work done by the net force during the displacement from x=0 to x=2m
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w=f×d
=m×a×d
a= differentiation of v
a=5×(3÷2)×x
a=5×1.5×2
a=15
w=0.5×15×2
w=15
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=m×a×d
a= differentiation of v
a=5×(3÷2)×x
a=5×1.5×2
a=15
w=0.5×15×2
w=15
mark me braineast Pls
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