Physics, asked by AryanB3308, 1 year ago

A particle of mass m =0.5 kg travels in a straight line with velocity v=5x^3/2 find the work done by the net force during the displacement from x=0 to x=2m

Answers

Answered by jenny997
3
w=f×d
=m×a×d
a= differentiation of v
a=5×(3÷2)×x
a=5×1.5×2
a=15
w=0.5×15×2
w=15
mark me braineast Pls

Similar questions